Springtime for T110 and the Americas
Дата: 23.10.2014 20:37:04
Slakrrrrrr, on Oct 23 2014 - 04:33, said: Alright, this question is going to take a lot of background, but
I'm curious to see your opinions. On a recent physics
quiz, I had a question involving finding average velocity.
Essentially, a person walks from point A to B at 5m/s, then walks
from B to A immediately after at 3m/s. The method at which I found
this average was this: give A to B a value (I gave it 10m, it could
honestly be anything and the resulting average velocity would be
the same), and use it to find a total time taken for the person to
walk from A to B (2s) and back to A (3.33s) for a total elapsed
time of 5.33s. I then divided the AB time by the total time, and
multiplied by the velocity ([2s/5.33s]x5m/s), and the same for the
BA time and velocity ([3.33s/5.33s]x3m/s), both resulting in 1.875.
The sum of these two values gave me the average velocity, 3.75m/s.
All of the steps listed above were clearly instructed on the quiz.
My question is this: should this method be considered
unconventional? To me, it seems pretty logical and unambiguous,
especially when the content is essentially review of high school
physics. Here's a picture
of the question on the quiz (apologies for the bad quality, the
pic was taken from my phone).The_Chieftain: Isn't the answer '0'? Velocity is a function of speed
and direction. If you're at the place when the stopwatch ends as
you were when it started, your overall average velocity must have
been 0.
Springtime for T110 and the Americas














